Monday, February 18, 2013

IBPS Bank PO Clerical and Specialists Officers Previous Years Quantitative Aptitude Questions with Answers and Detailed Explanations


IBPS Bank PO Clerical and Specialists Officers Previous Years Quantitative Aptitude Questions with Answers and Detailed Explanations


Directions (Q. Nos.1 to 5)

What will come in place of Question Mark (?) in the following Questions ?

1. 348 ÷ 29 x 15 + 156 = (?)3 + 120

(1) 12

(2) 6 (Ans)  

 (3) 36

(4) 9

(5) None of these

Explanation:

348 ÷ 29 x 15 + 156 = (?)3 + 120

       12 x 15 + 156 = (?)3 + 120

    180 + 156 - 120 = (?)3

                    216 = (?)3

                    (6)3 =  (?)3

                        ? = 6

  

2. (4 x 4)3 ÷ (512 ÷ 8)4 x (32 x 8)4 = (2 x 2)? + 4

(1) 8

(2) 12

(3) 6 (Ans)

(4) 14

(5) None of these

Explanation:

 (4 x 4)3 ÷ (512 ÷ 8)4 x (32 x 8)4 = (2 x 2)? + 4

     (16)3 ÷ (64)4 x (256)4 = (4)? + 4

    (4)2x3 ÷ (4)3x4 x (4)4x4  = (4)? + 4

          (4)6 ÷ (4)12 x (4)16 = (4)? + 4

                        (4)6-2+16 = (4)? + 4

                             (4)10  = (4)? + 4

                                 10 = ? + 4

                                   ? = 6



3. (2√392 - 21) + (√8 - 7)2 = (?)2

(1) 4

(2) -4

(3) 12

(4) 2

(5) 6 (Ans)

Explanation:

 (2√392 - 21) + (√8 - 7)2 = (?)2

                 (2 x 14√2 - 21) + (√8 - 7)2 = (?)2

   28√2 - 21 + (√8)2 - 2 x √8 x 7 + (7)2 = (?)2

                  28√2 - 21 + 8 - 28√2 + 49 = (?)2

                                     - 21 + 8 + 49 = (?)2

                                                     36 = (?)2

                                                       ? = 6



4. 1 1/4 + 1 1/6 - 1 1/8 = ? + 1 1/12

(1) 5/24 (Ans)

(2) 7/24

(3) 5/12

(4) 7/12

(5) None of these

Explanation:

1 1/4 + 1 1/6 - 1 1/8 = ? + 1 1/12

                 1 1/4 + 1 1/6 - 1 1/8 - 1 1/12  = ?            

   (1 + 1 - 1 - 1) + (1/4 + 1/6 - 1/8 - 1/12) = ?

   0 + (6 + 4 - 3 - 2/24) = ?      0 + 5/24 = ?

                                                    ? = 5/24



5. 76% of 1285 = 35% of 1256 + ?

(1) 543

(2) 537 (Ans)

(3) 547

(4) 533

(5) None of these

Explanation:

76% of 1285 = 35% of 1256 + ?

                 976.6 = 439.6 + ?

      976.6 - 439.6 = ?

                       ? = 537



Directions (Q. Nos. 6 to 10)

What  approximate value will come in place of Question Mark (?) in the following Questions? (You are not expected to calculate the exact value) You can take approximate value of any number

6. 499.99 + 1999 ÷ 39.99 x 50.01 = ?

(1) 3200

(2) 2700

(3) 3000 (Ans)

(4) 2500

(5) 2400

Explanation:

499.99 + 1999 ÷ 39.99 x 50.01 = ?

500 + 2000 ÷ 40 x 50 = ?

           500 + 50 x 50 = ?

               500 + 2500 = ?

                        3000 = ?



7. [(7.99)2 - (13.001)2 + '(4.01)3]2 = ?

(1) -1800

(2) 1450

(3) -1660

(4) 1660 (Ans)

(5) -1450

Explanation:

 [(7.99)2 - (13.001)2 + '(4.01)3]2 = ?

                       [(8)2 - (13)2 + (4)3]2 = ?

                             [64 - 169 + 64]2 = ?

                                           (-41)2 = ?

                                                  ? =  1681     (- x - +)

                                                   ≈ 1660



8. 601/49 x 399/81 ÷ 29/201 = ?

(1) 520

(2) 360

(3) 460

(4) 500

(5) 420 (Ans)

Explanation:

601/49 x 399/81 ÷ 29/201 = ?

       601/49 x 399/81 x 201/29 = ?

       600/50 x 400/80 x 200/30 = ?

        400 = ?

           420 ≈ ?



9. 441.01 - 232.99 + 1649.99 = ? + 1225.92

(1) 600

(2) 630 (Ans)

(3) 660

(4) 690

(5) 720

Explanation:

441.01 - 232.99 + 1649.99 = ? + 1225.92

         441 - 233 + 1650 - 1226  = ?

                           2091 - 1459 = ?

                                          ? = 623 ≈ 630



10. (21.5% of 999)1/3 + (43% of 601)1/2 = ?

(1) 18

(2) 22 (Ans)

(3) 26

(4) 30

(5) 33

Explanation:

 (21.5% of 999)1/3 + (43% of 601)1/2 = ?

         (1000 X 21.5%)1/3 + (600 X 43%)1/2 = ?

                                 (215)1/3 + (258)1/2 = ?

                                 (216)1/3 + (256)1/2 = ?

                                (6)3X1/3 + (16)2X1/2 = ?

                                                  6 + 16 = ?

                                                        22 = ?



Directions (Q. Nos. 11 to 15)

What will come in place of Question Mark (?) in the following number series?

 11. 15  21  39  77  143  (?)

(1) 243

(2) 240

(3) 253

(4) 245

(5) None of these (Ans)


12. 33  39  57  87  129  (?)8

(1) 183 (Ans)

(2) 177

(3) 189

(4) 19
 Explanation:








13. 15  19  83  119  631  (?)

(1) 731 (Ans)

(2) 693

(3) 712

(4) 683

(5) None of these

Explanation:









14. 19  26  40  68  124  (?)

(1) 246

(2) 238

(3) 236 (Ans)

(4) 256

(5) None of these
 
15. 43  69  58  84  73 (?)

(1) 62

(2) 98

(3) 109

(4) 63

(5) None of these (Ans)

Explanation:








Directions (Q. Nos. 16 to 20)

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer

(1) if x > y

(2) if x ≥ y

(3) if x < y

(4) if x ≤ y

(5) if x = y or the relationship cannot be established

16.  I.  x2 - 11x + 24 = 0

    II.  2y2 - 9y + 9 = 0
 

Ans : 2 (x ≥ y)   

Explanation:

I.  x2 - 11x + 24 = 0

              x2 - 8x - 3x + 24 = 0

            x (x - 8) - 3 (x - 8) = 0

                    (x - 8)(x - 3) = 0

        x = 8 or 3
 

II.       2y2 - 9y + 9 = 0

    2y2 - 6y - 3y + 9 = 0

 2y(y - 3) - 3 (y - 3) = 0

       (2y - 3) (y - 3) = 0

        y = 3/2 or 3

So,      x ≥ y



17.  I.  x3 * 13 =  x2 * 247 

   II.  y1/3 * 14  = 294 ÷ y2/3
 

Ans : 3 (y > x)

Explanation:

I.  x3 * 13 =  x2 * 247 

or x3 / x2  = 247/13

x = 19



II.          y1/3 * 14  = 294 ÷ y2/3    

or,   (y)1/3 * (y)2/3  = 294/14

or,          (y)1/3+2/3 = 21

                      y = 21

So,                     y > x





18.  I. 12 *  4 / x4/7 -  3 * 4 / x4/7 =  x10/7

    II.  y3 + 783 = 999
 

Ans : 4 (y ≥ x) 

Explanation: 

I. 12 *  4 / x4/7 -  3 * 4 / x4/7 =  x10/7

or,         48 - 12 = (x)10/7 * (x)4/7

or,         36 = (x)7     = (x)2

           x = ±6
 

II.          y3 + 783 = 999

                     y3 = 999 - 783

                     y3 = 216

                  y = ±6

                  y ≥ x



19.  I. √500 x + √402 = 0

    II. √360 y + (200)1/2 = 0
 

Ans : 5 (relationship cannot established)

Explanation: 

I. √500 x + √402 = 0

or,                           √500 x = - √402

By squaring both sides, we get

         500 x= 402

                 x = √402 /500 = ± 0.897



II. √360 y + (200)1/2 = 0

or,              (200)1/2 = - √360 y

By squaring both sides, we get

                200 = 360 y2

                    y = √200/360 = ± 0.75

relationship cannot established.






20.  I. (17)2 + 114 ÷ 18 = x

    II. (26)2 - 18 * 21 = y

Ans : 3 (y > x)   

Explanation:     

I. (17)2 + 114 ÷ 18 = x

                                 289 + 8 = x

                                        x = 297


II. (26)2 - 18 * 21 = y

           676 - 378 = y

                298 = y

So,                  y > x



21.The respective ratio between the present age of Ram and Rakesh is 6 : 11. Four years ago, the ratio of their ages was 1 : 2  respectively. What will be Rakesh's age after five years ?

(1) 45 years

(2) 29 years

(3) 49 years (Ans)

(4) Cannot be determined

(5) None of these

Explanation:    

Let the age of Ram = x and Rakesh = y then x/y = 6/11

  x = 6y/11

According to question,  x - 4/y - 4 = 1/2

                                       2x - 8 = y - 4

                             2 * 6y/11 - 8 = y - 4

                                 12y/11 - y = - 4 + 8

                                         y/11 = 4

                                           y =  44 yr

   Age of Rakesh after 5 yr

                                   = 44 + 5 = 49 yr



22. The circumference of two circles is 83 m and 220 m respectively. What is the difference between the area of the larger circle and the smaller circle?

(1) 3422 sq m

(2) 3242 sq m

(3) 3244 sp m  

(4) 3424 sq m

(5) None of these  (Ans)

Explanation: 

2 π r = 88

          r = 88 * 7/44  = 14 m

     Area = Ï€ r2

                = 22/7 * 14 * 14

                = 616 m2

        2Ï€ r1 = 220

             r1 =  220 * 7/2 * 22 = 35 m

    Area = Ï€ r12 = 22/7 * 35 * 35 = 3850 m2

Difference = 3850  -  616 = 3234 m2



23. One of the angles of a triangle is two-third angle of sum of adjacent angles of parallelogram. Remaining angles of the triangle are in ratio 5 : 7 respectively. What is the value of second largest angle of the triangle ?

(1) 250

(2) 400

(3) 350 (Ans)

(4) Cannot be determined

(5) None of these

Explanation: 

An angle of a triangle = 2/3 * 1800 = 1200

Remaining 1800 - 1200 = 600 is the ratio of 5 : 7.

So,               5x + 7x  = 60

                          12x = 60

                             x = 5

So, angles are 5 * 5 = 250

and 7 * 5 = 350

and         1200

So, value of second largest angle of triangle is 350 .



24. Pradeep invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total sum of their investment is Rs. 17880, how much amount did Raghu invest  ??

(1) Rs.6000(Ans)

(2) Rs.8000

(3) Rs.7000

(4) Rs.5000

(5) None of these

Explanation:    

Let the investment by Raghu = x

then Mohit = x * 90/100 = 9x/10

Pradeep = 9x/10 * 120/100 = 108x/100

According to question, x + 9x/10 + 108x/100 = 17880

100x + 90x + 108x/100 = 17880

298x/100 = 17880

x = 6000



25. Average score of Rahul, Manish and Suresh is 63. Rahul's score is 15 less than Ajay and 10 more than the average scores of Rahul, Manish and Suresh, what is he sum of Manish's and Suresh's scores ?

(1) 120

(2) 111 (Ans)

(3) 117

(4) Cannot be determined

(5) None of these

Explanation:     

Let the score of Ajay = x

            Rahul              = x - 15

            Manish            = x - 25

According to question, x = 63 + 30

                             x = 93

  Score of Ajay           = 93

then Rahul                   = 93 - 15 =78

then Manish                 = 93 - 25 = 68

Total marks of Rahul, Manish and Suresh = 3 * 63 = 189

    Suresh = 189 - (78 + 68) = 43

    Manish + Suresh = 68 + 43 = 111



26. Fifty-three per cent of a number is 358 less than the square of 26. What is the value of three-fourth of 23 per cent of that number?

(1) 101

(2) 109.5

(3) 113

(4) 103.5 (Ans)

(5) None of these
 

Explanation:     

 (26)2 - 358 = x * 53/100

                  318 = x * 53/100

                   x = 600

Again 600 * 3/4 * 23/100 = 103.5



27. The average speed of a car is 1 4/5 times the average speed of a bus. A tractor covers 575 km in 23 hours. How much distance will  the car cover in 4 hours if the speed of the bus is twice speed of the tractor?

(1) 340 km

(2) 480 km

(3) 360 km (Ans)

(4) 450 km

(5) None of these

Explanation:     

Average speed of a tractor =575/23 = 25 km/h

The speed of a bus in an hour = 25 * 2 = 50 km

The speed of a car in an hour = 50 * 9/5 = 90 km

So, the distance covered by car in 4 h is

                               90 * 4 = 360 km



28. The simple interest accrued on a sum of certain principal is Rs.2000 in five years at the rate of 4% per annum. What would be the compound interest accrued on same principal at same rate in two years?

(1) Rs.716

(2) Rs.724

(3) Rs.824

(4) Rs.816 (Ans)

(5) None of these

Explanation:     

2000 = P * 4 * 5/100

    P = 10000

Now,     CI = 10000[(1 + 4/100)2 - 1]

                = 10000 * 0.0816

                = 816


29. Rehaan purchased a bike for Rs.54000. He sold it at a loss of 8 per cent. With that money he again purchased another bike and sold it at a profit of 10 per cent. What is his overall loss/profit?

(1) Loss of Rs.657

(2) Profit of Rs.567

(3) Loss of Rs.648

(4) Profit of Rs.648 (Ans)

(5) None of these

Explanation:     

Cost price = 54000

Selling price = 54000 * (100-8)/100 = 49680

Now, the cost price of another bike = 49680

Selling price of another bike = 49680 * 110/100 = 54648

Overall profit = 54648 - 54000 = 648



30. Two men alone or three women alone can complete a piece of work in 4 days. In how many days can one woman and one man together complete the same piece of work?

(1) 6 days 

(2) 24/5 days (Ans)

(3) 12/1.75 days

(4) Cannot be determined

(5) None of these

Explanation:     

2M = 3W

   1M = 3/2 W

   1M + 1W = 3/2 W + 1W = 5/2 W

Number of days = 3 * 4/5/2 = 24/5 days



Directions (Q. Nos. 31 to 35)

Study the table carefully to answer the questions that follow

Number of employees working in four different companies in five different years

Year
Company
A
B
C
D
Male
Female
Male
Female
Male
Female
Male
Female
2004
2005
2006
2007
2008
200
250
400
650
750
400
150
250
400
300
250
400
850
500
600
450
100
400
150
350
350
550
350
650
400
600
350
500
500
300
400
550
650
700
650
450
600
450
600
400




31. What was the total number of males working in Company-A in the year 2007, males working in Company-B in the year 2005 and females working in Company-D in the year 2006 together ?

(1) 1550

(2) 1600

(3) 1450

(4) 1400

(5) None of these (Ans)

Explanation:     

Required number

= 650 + 400 + 450 = 1500



32. What was the average number of female employees working in all the companies together in the year 2004?

(1) 475 (Ans)

(2) 385

(3) 450

(4) 300

(5) None of these

Explanation:     

Average = 400 + 450 + 600 + 450/4

= 1900/4 = 475



33. Total number of male employees working in Company-C over all the years together was approximately what percentage of total number of employees working in the year 2007 in all the companies together?

(1) 41

(2) 46

(3) 51

(4) 55 (Ans)

(5) 59

Explanation:     

Total number of male employees working in company.  C over all the years together

= 350 + 550 + 350 + 650 + 400 = 2300

Total number of employees working in the companies in the year 2007 together

= 650 + 400+ 500 + 150 + 650 + 500 + 700 + 600 = 4150

Required percentage = 2300/4150 * 100

                             ≈ 55%



34. If 20 per cent of male and 30 per cent of female employees in Company-B in the year 2004 were handicapped, then what was the total number of handicapped candidates in that company in that year?

(1) 185 (Ans)

(2) 170

(3) 190

(4) 195

(5) None of these

Explanation:     

Handicapped employees in company. B in the year 2004

= 250 * 20/100 + 450 * 30/100

= 50 + 135 = 185


35. What was the respective ratio between the number of males in Company-D in the year 2005, number of females in Company-A in the year 2006 and the number of males in Company-B in the year 2005?

(1) 11 : 5 : 8 (Ans)

(2) 11 : 6 : 8

(3) 12 : 5 : 9

(4) 12 : 5 : 7

(5) 11 : 5 : 9

Explanation:     

Ratio = 550 : 250 : 400

= 11 : 5 : 8                        (Dividing by 50 to all)



Directions (Q. Nos. 36 to 40)

Study the following graph carefully to answer the questions that follow:
 
Number of students (in hundreds) from two different schools who qualified in an exam in six different years















36. What was the approximate per cent increase in the number of students who qualified in the exam from School-Q in the year 2007 as compared to the precious year ?

(1) 30

(2) 36

(3) 45 (Ans)

(4) 49

(5) 26

Explanation:     

Number of students in school Q in 2007

                        = 8000

and in year 2006 = 5500

           Increase = 8000 - 5500 = 2500

       % increase = 2500/5500 * 100 ≈ 45%



37. What was he respective ratio between the number of students who qualified in the exam from School- P in the year 2005 and the number of students who qualified in the exam from School-Q in the year 2008?

(1) 13 : 18

(2) 17 : 18 (Ans)

(3) 17 : 19

(4) 13 : 19

(5) None of these

Explanation:     

Ratio =  Student qualified from School P in 2005
                     Student qualified from School Q in 2008

                 = 85/90 = 17 : 18



38. What was the difference between the total number of students who qualified in the exam in the year 2005 from both the schools together and the total number of students from School-Q who qualified in the exam over all the years together?

(1) 30000 (Ans)

(2) 30500

(3) 29000

(4) 29500

(5) None of these

Explanation:     

Students qualified in 2005 from both the schools together

= (85 + 60) * 100 = 145 * 100 = 14500

Total number of students qualified from school over all the years together

= (60 + 55 + 80 + 90 + 75 + 85) * 100

= 445 * 100 = 44500

Difference = 44500 - 14500 = 30000



39. Total number of students who qualified in the exam from School-P over all the years together was approximately what percentage of total number of students who qualified in the exam from both the students who qualified in the exam from both the schools together in the year 2006 and 2007 together ?

(1) 143

(2) 159

(3) 155

(4) 165

(5) 147 (Ans)

Explanation:     

Total number of students, who qualified in the exam from school P over all the years together

= (85 + 80 + 95 + 65 + 40 + 90) * 100

= 455 * 100 = 45500

Total number of students, who qualified in the exam from both the schools together in the 2006 and 2007 years together

= (80 + 55 + 95 + 80 +) * 100

= 310 * 100 = 31000

Required percentage = 45500/31000 * 100 ≈ 147%



40. If 40 per cent  of the total students who qualified in the exam from both the schools together over all the years are females, then what was the total number of males who qualified in the exams over all the years from both the schools together?

(1) 51000

(2) 54000 (Ans)

(3) 56000

(4) 52000

(5) None of these

Explanation:     

Total number of students, who qualified in the exam over all the years from both the schools together

= (85 + 60 + 80 + 55 + 95 + 80 + 65 + 90 + 40 + 75 + 90 + 85) * 100

= 900 * 100 = 90000

∴    Required number of males

= 90000 * 60/100

= 54000   [Since females are 40%]



Directions (Q. Nos. 41 to 45)

 Study the following pie-chart carefully to answer the questions that follow:















 41. What was the approximate average number of passengers in Train-S, Train-M and Train-L together?

(1) 1521

(2) 1641

(3) 1651

(4) 1671 (Ans)

(5) 1691

Explanation:     

Average number = 8500 * (24 + 20 + 15)  ≈ 1671
                                                100
                                                  3



42. If in Train-R 34 per cent of the passengers are females and 26 per cent are children, what is the number of males in that train?

(1) 306 (Ans)

(2) 316

(3) 308

(4) 318

(5) None of these

Explanation:     

Number of passengers in train R

= 8500 * 9/100 = 765

Number of males = 765 * (100-34-26)  = 306
                                          100



43. Number of passengers in the Train-Q is approximately what percentage of the total number of passengers in Train-A and Train-R?

(1) 90

(2) 70

(3) 75

(4) 80

(5) 86 (Ans)

Explanation:     

Number of passengers in train Q

= 8500 * 19/100 =  1615

Total number of passengers in train A and train R

= 8500 * 13 + 9 /100 = 1870

∴    Required percentage = 1615/1870 * 100

≈ 86%



44. Which train has second highest number of passengers?

(1) A

(2) Q

(3) S

(4) M (Ans)

(5) L

Explanation:     

Train M (because having second highest percentage ).



45. How much more per cent (approximately) number of passengers are there in Train-M as compared to the number of passengers in Train-L?

(1) 29

(2) 49

(3) 43

(4) 33 (Ans)

(5) 39

Explanation:     

Number of passengers in train M

= 8500 * 20/100 = 1700

Number of passengers in train L

= 8500 * 15/100 = 1275

Required percentage = 1700 - 1275 * 100 ≈ 33%
                                     1275



Directions (Q. Nos. 46 to 50)

Study the following table carefully to answer the questions that follow:


Monthly rent (in Rs. thousands) at five different places in six different years

Year
Place
Church-gate
Dadar
Kandivali
Borivali
Virar
2005
2006
2007
2008
2009
2010
5.3
12.5
16.7
20.9
25.8
30.3
3.8
8.3
11.7
13.6
14.5
20.9
1.5
3.4
5.5
9.8
11.5
15.6
2.7
4.8
6.6
12.7
14.1
15.9
1.1
2.1
1.8
3.6
5.5
7.8



46. In which place, the monthly rent did not increase consistently from year 2005 to 2010 ?

(1) Churchgate

(2) Dadar

(3) Kandivali

(4) Borivali

(5) Virar (Ans)



47. In which year at Churchgate, the monthly rent increased more than 100% from the previous year?

(1) 2006 (Ans)

(2) 2007

(3) 2008

(4) 2009

(5) 2010

Explanation:     

2006 [12.5 - 5.3/5.3 * 100 = 135.85%]



48. What was the difference between the monthly rent at Dadar in the year 2009 and Borivali in the year 2007?

(1) Rs. 7600

(2) Rs. 7900 (Ans)

(3) Rs. 8100

(4) Rs. 8600

(5) None of these

Explanation:     

Required difference = (14.5 - 6.6) 1000 = 7900



49. Monthly rent at Kandivali in the year 2008 was approximately what per cent of the total montly rent at Virar over all the years together?

(1) 30

(2) 33

(3) 38

(4) 42

(5) 45 (Ans)

Explanation:     

Required percentage

=                   9.8 * 100                       ≈ 45%
     1.1 + 2.1 + 1.8 + 3.6 + 5.5+ 7.8



50. Which city was most expensive in terms of rent?

(1) Churchgate (Ans)

(2) Dadar

(3) Kandivali

(4) Borivali

(5) Virar 

Explanation:     

Because of highest average among all.










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